【答案】有如下函数过程:Function secproc(x As Integer, y As Integer, z As In

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有如下函数过程:Function secproc(x As Integer, y As Integer, z As Integer) secproc = 3 y + z + 2 xEnd Function Private Sub Command1_Click() Dim a As Integer, b As Integer, c As Integer a = 2: b = 3: c = 4 Print secproc(c, b, a)End Sub该程序的运行结果是()。

A.17

B.18

C.19

D.20

正确答案:19

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